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A point objects O is nat angle of 30^(@)from the plane mirror M, as shown In the figure. If OO'=2m, then find the location of the image |
Answer» Solution :To find the location of IMAGE, we have to draw a perpendicular on the mirror M from the point O as shown in the FIGURE. Now from the triangle O' AO, we have `sin30^(@)=(OA)/(2)rArrOA=2xxsin30^(@)=1M` `therefore`Distance of the image from the mirror is AI=OA=1m |
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