1.

A point P al a certain distance from charge Q has electric potential 600 V and elecuic field intensity 150 N/C, lhen distance of point from charge Q is ...... M.

Answer»

4
2
`3.2`
`6.5`

Solution :Electric POTENTIAL = V = Ed
`:. D=(V)/(E)= (600)/(150) =4 m`


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