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A point source of light S, placed at a distance L in front of the centre of a mirror of width d, hangs vertically on a wall. A man walks in front of the mirror along a line parallel to the mirror at a distance 2L from it as shown in figure. Find the greatest distance over which he can see the image of the light source in the mirror. |
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Answer» Solution :The ray diagram will be as shown in Figure. HI =AB=d, DS=CD=d/2 Since, AH=2AD, ` thereforeGH = 2CD= 2 (d)/(2) = d ` SIMILARLY IJ = d GJ = GH+HI+IJ = d+d+d=3d
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