A point source of power `50pi` watts is producint sound waves of frequency `1875Hz`. The velocity of sound is `330m//s`, atmospheric pressure is `1.0xx10^(5)Nm^(-2)` density of air is `1.0kgm^(-3)`. Then pressure amplitude at `r=sqrt(330)m` from the point source is (using `pi=22//7`:A. `5Nm^(-2)`B. `10Nm^(-2)`C. `15Nm^(-2)`D. `20Nm^(-2)`

A point source of power `50pi` watts is producint sound waves of frequ

1.	A point source of power `50pi` watts is producint sound waves of frequency `1875Hz`. The velocity of sound is `330m//s`, atmospheric pressure is `1.0xx10^(5)Nm^(-2)` density of air is `1.0kgm^(-3)`. Then pressure amplitude at `r=sqrt(330)m` from the point source is (using `pi=22//7`:A. `5Nm^(-2)`B. `10Nm^(-2)`C. `15Nm^(-2)`D. `20Nm^(-2)`
Answer» Correct Answer - A `I=(P_0^2_)/(2rhoV)implies(P)/(4pir^2)=(P_0^2)/(2rhoV)`, where P,`P_0`,`V` are power pressure amplitude and velocity respectively. `impliesP_0=sqrt((PrhoV)/(2pir^2))=sqrt((50pixx1xx330)/(2pixx330))=5`

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