1.

A string of length 2 m is fixed at both ends. If this string vibrates in its fourth normal mode with a frequency of 500 Hz then the waves wouldf travel on it is with a velocity ofA. `125 m//s`B. `25m//s`C. `500 m//s`D. `1000 m//s`

Answer» Correct Answer - C
For string `lamda=(2l)/(p)`
where `p=` No. of loops`=`Order of vibration
Hence for fourth mode `p=4implieslamda=(l)/(2)`
hence `v=nlamda=500xx(2)/(2)=500Hz`


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