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Thw two nearest harmonics of a tube closed at one end and open at other end are 220 Hz and 260 Hz. What is the fundamental frequency of the system?A. `20 Hz`B. `30 Hz`C. `40 Hz`D. `10 Hz` |
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Answer» Correct Answer - A Two successive frequencies of closed pipe `(nv)/(4l)=220` `((n+2)v)/(4l)=260` Dividing (ii) by (i) we get `((n+2))/(n)=(260)/(220)=(13)/(11)impliesn=11` so from (i), `(11xxv)/(4l)=220` `implies(v)/(4l)=20Hz` So fundamental frequency `=20Hz` |
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