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Thw two nearest harmonics of a tube closed at one end and open at other end are 220 Hz and 260 Hz. What is the fundamental frequency of the system?A. `20 Hz`B. `30 Hz`C. `40 Hz`D. `10 Hz`

Answer» Correct Answer - A
Two successive frequencies of closed pipe
`(nv)/(4l)=220`
`((n+2)v)/(4l)=260`
Dividing (ii) by (i) we get
`((n+2))/(n)=(260)/(220)=(13)/(11)impliesn=11`
so from (i), `(11xxv)/(4l)=220`
`implies(v)/(4l)=20Hz`
So fundamental frequency `=20Hz`


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