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A point starts from rest and moves along a circular path with a constant tangential acceleration. After one rotation, the ratio of its radial acceleration to its tangential acceleration will be equal toA. 1B. `2pi`C. `(1)/(2)pi`D. `4pi` |
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Answer» Correct Answer - D `(a_(n))/(a_(t))=(v^(2)//R)/(a)" "("let a"_(t)=a)` Here, `v^(2)=2al=2a(2piR)=4piR`. Therefore, the ratio is `(4pi)/(1)`. |
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