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A point starts with the velocity 10 cm/sec and moves along a straight line with uniform acceleration 5cm/sec^2. How much time it takes to describe 80 cm?(a) 4 seconds(b) 2 seconds(c) 8 seconds(d) 6 secondsI had been asked this question in an interview for job.This interesting question is from Calculus Application topic in portion Application of Calculus of Mathematics – Class 12

Answer»

Right option is (a) 4 SECONDS

To elaborate: Let us assume that the POINT takes t seconds to describe a distance 80 cm.

Then using the formula s = UT +1/2(ft^2) we get,

80 = 10*t + 1/2(5)(t^2)

Or 5t^2 + 20t – 160 = 0

Or t^2 + 4t – 32 = 0

Or (t – 4)(t + 8) = 0

Or t = 4 Or -8

Clearly, t = -8 is inadmissible.

Therefore, the required time = 4 seconds.


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