A polarized light of intensity I_(0) is passed through another polarizer whose pass axis makes an angle of 60^(@) with the pass axis of the former.What is the intensity of emergent polarized light from second polarizer ?

A polarized light of intensity I_(0) is passed through another polariz

1.	A polarized light of intensity I_(0) is passed through another polarizer whose pass axis makes an angle of 60^(@) with the pass axis of the former.What is the intensity of emergent polarized light from second polarizer ?
Answer» `I = I_(0)` `I = (I_(0))/(6)` `I = (I_(0))/(5)` `(I_(0))/(4)` Solution :By Malus LAW, `I = I_(0) cos ^(2) THETA` (I = Intensity of emergent polarized light) where `theta = 60^(@), I = ?` (`I_(0)` = Intensity passed through polariser) ` = I_(0) xx ((1)/(2))^(2) = (I_(0))/(4)`

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A polarized light of intensity I_(0) is passed through another polarizer whose pass axis makes an angle of 60^(@) with the pass axis of the former.What is the intensity of emergent polarized light from second polarizer ?

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