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A population inversion for two energy levels is often described by assigning a negative Kelvin temperature to the system. What negative temperature would describe a system in which population of the upper energy level exceeds that of the lower by 10% and the energy difference between the two levels is 2.2 eV? |
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Answer» Solution :As `N_(X)=N_(0)e^(-(E_(x)-E_(0))//kT) :. (N_(x))/(N_(0))e^(-(E_(x)-E_(0))//kT)` `ln ((N_(x))/(N_(0)))=-(E_(x)-E_(0))/(kT)` or `-T=(E_(x)-E_(0))/(K ln((N_(x))/(N_(0))))` Now, `E_(x)-E_(0)=2.2eV and (N_(x))/(N_(0))=1.10, k=8.62xx10^(-5)eV//K` `:. -T=(2.2eV)/((8.62xx10^(-5)eV//K)ln(1.10))=2.67xx10^(5)K or T=-2.67xx10^(5)K` |
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