Saved Bookmarks
| 1. |
A positive charge of 1.5 muC is moving with a speed of 2 xx 10^(-6) ms^(-1) along the postive X-axis. A magnetic field,vec(B) = (0.2 hat(j) + 0.4 hat(k)) tesla acts in space. Find the magnetic force acting on the charge. |
|
Answer» SOLUTION :Here q = 1.5`mu`C = 1.5 `xx 10^(-6)` C `vec(V) = 2xx 10^(6) hat(i) MS^(-1) : vec(B) = (0.2 hat(j) + 0.4 hat(k))`T Magnetic FORCE on the positive charge is `vec(F) = q (vec(v) xx vec(B))` = `1.5 xx 10^(-6) [ 2 xx 10^(6) hat(i) xx (0.2 hat(j) + 0.4 hat(k)) ] ` = 3.0` [ 0.2 HATI xx hatj + 0.4 hati xx hatk ]` `= (0.6 hatk - 1.2 hatj ) N"" [ because i xx hatj = hatk, hati xx hatk = - hatj]` |
|