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A positive charge particle of charge q, mass m enters into a uniform magnetic field with velocity v as shown in the figure. There is no magnetic field to the left of PQ.Find impulse of magnetic force. |
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Answer» Solution :The particle will MOVE in the field as shown. Angle subtended by the ARC at the centre = `2theta` Impulse = change in momentum of the CHARGE `=(-mvsinthetahati+mvcosthetahatj)` `-(mvsinthetahati+mvcosthetahatj)=-2mvsinthetahati` |
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