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A positive charge particle of charge q, mass m enters into a uniform magnetic field with velocity v as shown in the figure. There is no magnetic field to the left of PQ.Find distance travelled in the magnetic field |
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Answer» Solution :The PARTICLE will move in the FIELD as shown. Angle subtended by the arc at the centre = `2theta` DISTANCE travelled by the CHARGE in magnetic field : `=r(2theta)=(MV)/(qB).2theta`
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