1.

A positively charged ball hang a silk thread. We put a positive test charge q_(0) at a point and measure F//q_(0), then it can be predicted that the electric field strength E.

Answer»

`GT F//q_(0)`
`=F//q_(0)`
` lt F//q_(0)`
Can not be estimated

Solution :Because of the presence of positive test charge `q_(0)` in FRONT of positively charged BALL, charge on the ball will be redistributed, less charge on the front half surface and more charge on the back half surface. As a result of this NET force `F` between ball and point charge will decrease i.e., actual electric FIELD will be greater than `F//q_(0)`


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