InterviewSolution
 Saved Bookmarks
    				| 1. | 
                                    A potentiometer is being used to determine the internal resistance of a primary cell. The balance point for the cell in an open circuit is at 76.3 cm. when the cell sends a current in a resistor of `9.5Omega`, the balance point shifts to 64.8cm. Find the internal resistance of the cell. | 
                            
| 
                                   
Answer» Correct Answer - `1.68Omega` | 
                            |