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A potentiometer wire , 4 m long and having a resistance of 10 Omega, is connected in series with an external resistance of 38 Omega and a cell , ofemf 2 V and internal resistance 2 Omega. Calculate thepotential gradient along the wire. |
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Answer» Solution :Date : ` L = 4 m , R = 10 Omega, E = 2 V, r_(C) = 2 Omega, R = 39 Omega` The POTENTIAL difference across the wire is `V = Ir = (E/(r + r_(c) + R))r` ` :. ` The potential gradient along the wire is ` V/L = (Er)/((r + r_(c )+R)L) ` ` =(2 xx 10)/((10 + 2 + 38) xx4) ` ` = (20)/(50 xx 4) = 20/200 = 0.1` V/m |
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