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A potentiometer wire of length 10 m is connected in series with a battery the emf of a cell balances against 250 cm length of wire if length of potentiometer wire is increased by 1 m then new balancing length of wire will beA. 2.00 mB. 2.25 mC. 2.50 mD. 2.75 m |
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Answer» Correct Answer - a Balancing condition of potentiometer is given by if `I_(1)` is incressed by 1m then new length will `I_(1)=10m+1m=11m` `therefore` new balancing length of wire `(l_(2))` is `(mu^_(1))/(l_(2))=(E_(1))/(E_(2)) rarr (11)/(l_(2))=4 therefore L_(2)=11/4=2.75 m` |
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