1.

A precipitate of ____would be obtained on adding HCl to a solution of (Sb_(2)S_(3)) in yellow ammonium sulphide

Answer»

`Sb_(2)S_(3)`
`Sb_(2)S_(3)`
`SbS`
`SbS_(2)`

Solution :`Sb_(2)S_(3)+2(NH_(4))_(2)S_(2) to 2(NH_(4))_(2)S+Sb_(2)S_(5)`


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