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A preson is standing on the centre of a rotating table with his arms outstretched. The table is rotating freely with an angular his hands towards his chest. The moment of inertia reduces to `(3)/(5)` time the original moment of inertia. Calculate angular speed of the man when he withdraws his hands. |
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Answer» Let `I_(1) = I, omega_(1) = 24` rpm `I_(2) = (3)/(5)I, omega_(2) = ?` According to the law of conservation of angular momentum, `I_(2)omega_(2) = I_(1)omega_(1)` `omega_(2) = (I_(1)omega_(1))/(I_(2)) = (I xx 24)/(3//5I) = 40`rpm |
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