1.

A prism of a refracting angle 60^(@) is made with a material of refractive index mu. For a certain wavelength of light, the angle of minimum deviation is 30^(@). For this wavelength, the value of mu of material is

Answer»

1.82
1.414
1.503
1.231

Solution :`MU=(sin((60^(@)+30^(@))/(2)))/(sin30^(@))=(SIN45^(@))/(sin30^(@))=(1)/(SQRT(2))xx(2)/(1)=sqrt(2) = 1.414`


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