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A prism of angle 60^(0) produces angle of minimum deviation of 40^(0). What is its refractive index ? Calcualte the angle of incidence. |
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Answer» SOLUTION :Here : `A=60^(0),D=40^(0),n=?,i=?` we have `n=(Sin((A+D)/(2)))/(Sin((A)/(2)))` `=(Sin((60+40)/(2)))/(Sin((60)/(2)))` `=(Sin(50))/(Sin(30))=(0.7660)/(0.5000)` n = 1.532 At MINIMUM DEVIATION position `i=(A+D)/(2)=(60+40)/(2)=50^(0)` |
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