A prism of refractive index mu_1 = 1.42 and prism angle 10° is arranged with another prism of refractive index mu_2 = 1.7. If this combination gives the dispersion without deviation, then what should be the prism angle of second prism?

A prism of refractive index mu_1 = 1.42 and prism angle 10° is arrang

1.	A prism of refractive index mu_1 = 1.42 and prism angle 10° is arranged with another prism of refractive index mu_2 = 1.7. If this combination gives the dispersion without deviation, then what should be the prism angle of second prism?
Answer» `6^@` `8^@` `10^@` `4^@` Solution :For dispersion WITHOUT deviation `delta=0` `therefore delta=delta_1+delta_2` `0=(mu-1)A+(mu.-1)A.` `therefore A.=-((mu-1)A)/(mu.-1)` `=-((1.42-1)xx10)/((1.7-1))=-(0.42xx10)/(0.7)=-6^@` Negative sign represents that PRISM angles of prisms are opposite. `therefore` Prism ANGLE of second prism = `6^@`

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A prism of refractive index mu_1 = 1.42 and prism angle 10° is arranged with another prism of refractive index mu_2 = 1.7. If this combination gives the dispersion without deviation, then what should be the prism angle of second prism?

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