A prism of refractive index mu = 1.5 and prisim angle 15^@ is arranged with another prism ( refractive index mu_2 = 1.75. If this combination gives the dispersion without deviation, the what should be the prism angle of second prism ?

A prism of refractive index mu = 1.5 and prisim angle 15^@ is arranged

1.	A prism of refractive index mu = 1.5 and prisim angle 15^@ is arranged with another prism ( refractive index mu_2 = 1.75. If this combination gives the dispersion without deviation, the what should be the prism angle of second prism ?
Answer» `7^@` `10^@` `12^@` `5^@` SOLUTION :Deviation = zero Hence, `delta=delta_1+delta_2=0` `(mu_1-1)A_1+(mu_2-1)A_2=0` `A_2(1.75-1)=-(1.5-1)15^@` `A_2=-(0.5)/(0.75)xx15^@` `A_2=-10^@` negative sign represents that second prism is inversely CONNECTED with first prism.

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A prism of refractive index mu = 1.5 and prisim angle 15^@ is arranged with another prism ( refractive index mu_2 = 1.75. If this combination gives the dispersion without deviation, the what should be the prism angle of second prism ?

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