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A progressive wave is given by `y=3 sin 2pi [(t//0.04)-(x//0.01)]`where x, y are in cm and t in s. the frequency of wave and maximum accelration will be:A. `100 Hz,4.7xx10^(3) m//s^(2)`B. `50 Hz, 7.5xx10^(3) m//s^(2)`C. `25 Hz, 4.7xx10^(4) m//s^(2)`D. `25 Hz, 7.5xx10^(4) m//s^(2)` |
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Answer» Correct Answer - d We know `(omega)=2pif=(2pi)/(0.04)` `rArr f=285 Hz` Differented `y` w.r.t. twice, we have `y'(-3xx(4pi^(2)))/((0.004)^(2)) sin(2pi[((t)/(0.04))-((x)/(0.01))])` For maximum acceleration `y_(0)'(-3xx(4pi^(2)))/((0.004)^(2))=7.5xx10^(4) m//s^(2)` |
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