A projectile at its highest point, breaks into two equal parts due to an internal explosion. One part moves vertically up at 30 m/s with respect to ground. Then the other part will move with speed if (Speed just before explosion is 20 m/s) :

A projectile at its highest point, breaks into two equal parts due to

1.	A projectile at its highest point, breaks into two equal parts due to an internal explosion. One part moves vertically up at 30 m/s with respect to ground. Then the other part will move with speed if (Speed just before explosion is 20 m/s) :
Answer» `20m//s` `10sqrt(3) m//s ` 50 m/s 30 m/s Solution : ` vecP_(1)=vecP_(f)` `mxx20 hati= (m) /(2) xx30 HATJ+(m)/(2)XX VECV` ` vecv- 40hati- 30 hatj` ` \| vecv \| = 50`

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A projectile at its highest point, breaks into two equal parts due to an internal explosion. One part moves vertically up at 30 m/s with respect to ground. Then the other part will move with speed if (Speed just before explosion is 20 m/s) :

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