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A projectile is fired from the surface of earth of radius `R` with a velocity `k upsilon_(e)` (where `upsilon_(e)` is the escape velocity from surface of earth and `k lt 1)`. Neglecting air resistance, the maximum height of rise from centre of earth isA. `(1-k^(2))/R`B. `R/(1-k^(2))`C. `R(1-k^(2))`D. `R/(1+k^(2))` |
Answer» Correct Answer - B Using conservation of energy `1/2m(Kv_(e))^(2)-(GMm)/R=-(GMm)/(R+h)` Use `v_(e)=sqrt(2gR)` and `Gm=gR^(2)` and to solve we get `h+R=R//(1=K^(2))`. |
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