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A projectile is fired from the surface of earth of radius `R` with a velocity `k upsilon_(e)` (where `upsilon_(e)` is the escape velocity from surface of earth and `k lt 1)`. Neglecting air resistance, the maximum height of rise from centre of earth isA. `R/(n^(2))`B. `R/((1-n^(2))`C. `(Rn^(2))/((1-n^(2)))`D. `Rn^(2)` |
Answer» Correct Answer - C `1/2mv^(2)=(GMm)/R=(GMm)/(R+h)=(GMmh)/(R(R+h))=(mghR)/(R+h)` Since `v=nv_(3)` and `v_(3)=sqrt(2gR)` hence `=(Rn^(2))/(1+n^(2))` |
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