A projectile is fired vertically upwards. It escapes from theearth, when fired with velocity v. If it is to be fired at 45° tohorizontal, what should be its velocity to enable it toescape from the gravitational pull of the earth

A projectile is fired vertically upwards. It escapes from theearth, wh

1.	A projectile is fired vertically upwards. It escapes from theearth, when fired with velocity v. If it is to be fired at 45° tohorizontal, what should be its velocity to enable it toescape from the gravitational pull of the earth
Answer» <p>Escape velocity is the minimum velocity required for an object to move from Gravitational influence of a massive body . For example , in case of earth escape velocity , ve : 1/2mve² [ Kinetic energy of body ] = GMm/R [ gravitational potential energy between body and earth ]ve² = 2GM/Rve = √{2GM/R} or, √{2gR} </p><p>Here you can see that escape velocity of earth = √{2gR} , which is independent from angle of projection.So , escape velocity will be same , when a projectile is fired at 45° to the horizontal . </p><p>Hence, answer is v</p>