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A projectile is fired with initial momentum p at an angle `45^(@)` from a point P as shown in figure. Neglecting air resistance, the magnitude of change in momentum between leaving P and arriving at Q is: A. `p//2`B. `psqrt(2)`C. `p`D. `2p` |
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Answer» Correct Answer - b Initial momentum =p, Final momentum =-p Angle between momentum vectors `=270^(@)` |change in momentum| `=sqrt(p^(2)+(-p)^(2)+2p(-p)cos 270^(@))=sqrt(2)p` |
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