1.

A projectile is fired with velocity u making an angle θ with the horizontal. What is the angular momentum of the projectile at the highest point about the starting point ? (Given the mass of the projectile is m )

Answer»

`(m cos theta)/(2g)`
`(m u^(2)SIN^(2)theta cos theta)/(2g)`
`(m u^(3)cos^(2)theta)/(2g)`
`(m u^(3)sin^(@)theta costheta)/(2g)`

Solution :`"h = MAXIMUM height "=(u^(2)sin^(2)theta)/(2g)`
`"Linear MOMENTUM "=m u cos theta " at the highest"`
`"point ANGULAR momentum of the projectile at "`
`"the highest point"="linear momentum"XX"perpendicular distance"`
`=m u cos theta xx "h mu cos "theta=(u^(2)sin^(2)theta)/(2g)`
`=(m u^(2)sin^(2)theta cos theta)/(2g)`


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