A projectile is given an initial velocity of (hati + 2hatj) m/s, where hati is along the ground and hatj is along the vertical. If g = 10 m//s^(2) , the equation of its trajectory is:

A projectile is given an initial velocity of (hati + 2hatj) m/s, where

1.	A projectile is given an initial velocity of (hati + 2hatj) m/s, where hati is along the ground and hatj is along the vertical. If g = 10 m//s^(2) , the equation of its trajectory is:
Answer» `y=2x-5x^(2)` `4y=2x-5x^(2)` `4y=2x-25x^(2)` `y=x-5x^(2)` SOLUTION :Here x=t `:.y=2t-5t^(2)` EQUATION of TRAJECTORY `y=2x-5x^(2)`

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A projectile is given an initial velocity of (hati + 2hatj) m/s, where hati is along the ground and hatj is along the vertical. If g = 10 m//s^(2) , the equation of its trajectory is:

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