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A projectile is projected tangentially from the surface of a planet of radius R. If it is at a height of 3R at the farthest point of its trajectory, then the velocity of projection `V_(0)` is given by ( acceleration due to gravity on surface=g)A. `v_(0)=sqrt(1.5gR)`B. `v_(0)=sqrt(0.5gR)`C. `v_(0)=sqrt(1.6gR)`D. `v_(0)=sqrt(2gR//3)` |
Answer» Correct Answer - C | |