A projectile is projected with initial velocity (6hat(i) + 8hat(j)) ms^(-1) if g = 10 ms^(-2) , then horizontal range is :

A projectile is projected with initial velocity (6hat(i) + 8hat(j)) ms

1.	A projectile is projected with initial velocity (6hat(i) + 8hat(j)) ms^(-1) if g = 10 ms^(-2) , then horizontal range is :
Answer» 4.8m 9.6m 19.2m 14.0m Solution :Here `vec(v)=6hati +8hatj` `:. \|v\|=sqrt(6^(2)+8^(2))=10ms^(-1)` ALSO `vcostheta=6` and `vsintheta=8` `g=10ms^(-2)` `:.R=(2vcostheta.vsintheta)/g` `=(2xx6xx8)/10=9.6m`

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A projectile is projected with initial velocity (6hat(i) + 8hat(j)) ms^(-1) if g = 10 ms^(-2) , then horizontal range is :

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