1.

A projectile is thrown at an angle theta with the horizontal and its range is R_(1) It is then thrown at an angle 0 with vertical and the range is R_(2) then :

Answer»

`R_(1)=4R_(2)`
`R_(1)=2R_(2)`
`R_(1)=R_(2)`
`R_(1)=R_(2)/2`

Solution :RANGE is same for angle of projection `THETA` and `(90-theta):. R_(1)=R_(2)`


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