1.

A projectile of mass m is fired with velocity v from a point P at theta = 45°. Neglecting air friction, the magnitude of change of momentum between the leaving pt. P and arriving pt. Q is :

Answer»

`(MV)/sqrt(2)`
2MV
`1/2mv`
`sqrt(2)mv`

SOLUTION :`P_(1y)=mvsintheta,p_(2y)=-mvsintheta.` As `theta=45^@`
`:. |Deltap_(y)|=2mvsintheta=2mvxx1/sqrt(2)=sqrt(2)mv`


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