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A projective of 2kg was velocities 3mls and 4mls at two points during its flight in the uniform gravitational field of the earth. If these two velocities are botto each other then the minimum KE of the particle during its flight is |
Answer» Solution : `V_(1)cos alpha =V_(2)cos(90-alpha)` `3COS alpha=4 sin alpha` `tan alpha =3/4` `KE_("man") =1/2mv_(1)^(2) cos^(2)alpha` `1/2 xx 2 xx 3 xx (4/5)^(2) =(9 xx 16)/25 = 5.76` J |
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