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A projective of 2kg was velocities 3mn/ sand 4m/s of two points during its flight in the uniform gravitational field of the earth. If these two velocities are bot to each other then the minimum KE of the particle during its flight is |
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Answer» Solution :`V_(1) cos alpha= V_(2) cos (90- alpha)` `3 cos alpha=4 sin alpha` `tan alpha=(3)/(4)` `KE_("min")=(1)/(2) mv_(1)^(2) cos^(2) alpha` `=(1)/(cancel7)xx cancel2xx3((4)/(5))^(2)=(9xx16)/(25)=5.76J` 
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