A proton and alpha particle are accelerated through the same accelerating potential. Which one of the two has (a) greater value of de-broglie wavelength associated with it, and(b) less kinetic energy?justify your answer.

A proton and alpha particle are accelerated through the same accelerat

1.	A proton and alpha particle are accelerated through the same accelerating potential. Which one of the two has (a) greater value of de-broglie wavelength associated with it, and(b) less kinetic energy?justify your answer.
Answer» SOLUTION :(a) de Broglie WAVELENGTH `lambda=h/p=h/SQRT(2mqV)` For same V, `1=alpha 1/sqrt(mq)` `therefore (lambdad)/(lambdaalpha)=sqrt((malphaqalpha)/(m_dq_d))=sqrt((2m_dxx2q_d)/(m_dq_d))=2/1` `therefore lambda_alpha > K_alpha` (b) Kinetic ENERGY, K = qV So, `qalpha > K_d` For same V , we have `K alpha > K_d`

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A proton and alpha particle are accelerated through the same accelerating potential. Which one of the two has (a) greater value of de-broglie wavelength associated with it, and(b) less kinetic energy?justify your answer.

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