A proton and an alpha particle are accelerated through the same potential difference V. The ratio of their de Broglie wavelengths is

A proton and an alpha particle are accelerated through the same potent

1.	A proton and an alpha particle are accelerated through the same potential difference V. The ratio of their de Broglie wavelengths is
Answer» Solution :`LAMBDA=(h)/(p)=(h)/(SQRT(2mqV))` As `m_(ALPHA)=4m_(p)` and `q_(alpha)=2q_(p)` `(lambda_(alpha))/(lambda_(p))=sqrt((2m_(p)q_(p))/(2m_(alpha)q_(alpha)))=sqrt((m_(p)q_(p))/(4m_(p)2q_(p)))=sqrt((1)/(8))` `=(1)/(2sqrt2)`

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A proton and an alpha particle are accelerated through the same potential difference V. The ratio of their de Broglie wavelengths is

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