A proton and an alpha particle are accelerated, using the same potential difference How are the de Brogie wavelengths lambda_p and lambda_alpha are related to each other?

A proton and an alpha particle are accelerated, using the same potenti

1.	A proton and an alpha particle are accelerated, using the same potential difference How are the de Brogie wavelengths lambda_p and lambda_alpha are related to each other?
Answer» SOLUTION :By DE Broglie wavelength, `lambda=h/SQRT(2mqV) lambda_alpha 1/sqrt(mq)` Then `lambda_p/lambda_alpha=(sqrt(m_alpha q_alpha)/(sqrtm_pq_p))=(sqrt(4m_pxx2e)/(sqrt(m_pxxe))=sqrt(8)/1`

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A proton and an alpha particle are accelerated, using the same potential difference How are the de Brogie wavelengths lambda_p and lambda_alpha are related to each other?

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