1.

A proton and an alpha particle have same kinetic energy. Their de-Broglie wavelengths are in the ratio_____.

Answer»

Solution :`lamda_(p):lamda_(alpha)=2:1` [As PER relation `lamda=(H)/(sqrt(2mK))`, for same value of KINETIC ENERGY `lamdaprop(1)/(sqrt(m))`.].


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