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A proton and an electron have same de Broglie wavelength, which possesses more KE ? |
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Answer» SOLUTION :de Broglie wavelength of a particle of mass m and kinetic energy E is `LAMBDA = h/sqrt(2mE), mE = h^2/(2lambda^2), lambda` is then same for both PROTON ELECTRON . So, ,mE = a constant. The mass of proton `m_p gt` the mass of electron `m_e`. So, that energy of proton `E_P lt` the energy of electron `E_e`. ELECTRONS have more KE. |
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