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A proton and an electron have same kinetic energy. Which one has greater de Broglie wavelength. Justify. |
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Answer» SOLUTION :de-Broglie wavelength of the particle is `lambda = (h)/(p) = (h)/(SQRT(2mK))` i.E. `lambda prop (1)/(sqrt(m))` As `m_(e) lt lt m_(p)`, so `lambda_(e) gt gt lambda_(p)` Hence protons have GREATER de-Broglie wavelength |
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