1.

A proton beam enters a magnetic field of 10^(-4) " Wb " m^(-2)Wb normally. If the specific charge of the proton is10^(11) " C " kg^(-1) and its velocity is 10^(9) " m "s^(-1) then the radius of the circle described will be

Answer»

1m
100m
10m
0.1m

Solution :`r= (mv)/(QB) rArr r= (10^(9))/(10^(11) xx 10^(-4))= 10^(2)m = 100m`


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