A proton carrying `1 MeV` kinetic energy is moving in a circular path of radius `R` in unifrom magentic field. What should be the energy of an `alpha-` particle to describe a circle of the same radius in the same field?A. 1 MeVB. 0.5 MeVC. 4 MeVD. 2 MeV

A proton carrying `1 MeV` kinetic energy is moving in a circular path

1.	A proton carrying `1 MeV` kinetic energy is moving in a circular path of radius `R` in unifrom magentic field. What should be the energy of an `alpha-` particle to describe a circle of the same radius in the same field?A. 1 MeVB. 0.5 MeVC. 4 MeVD. 2 MeV
Answer» Correct Answer - A `r=(sqrt(2m(KE)))/(qB)` `q prop sqrt(m(KE))` `(e)/(2e)=sqrt(((m_(p))(1MeV))/((4m_(p))(KE)))` `(1)/(4)=(1)/(4(KE))` `KE=1MeV`

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A proton carrying `1 MeV` kinetic energy is moving in a circular path of radius `R` in unifrom magentic field. What should be the energy of an `alpha-` particle to describe a circle of the same radius in the same field?A. 1 MeVB. 0.5 MeVC. 4 MeVD. 2 MeV

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