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A proton falls freely under gravity of Earth.Its de-Broglie wavelength after 10s of its motion is ……….Neglect the forces other than gravitational force. (g=10 m//s^(2),m_(p)=1.67xx10^(-27)Kg,h=6.625xx10^(-34)Js) [similar as Oct. 2012,'15] |
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Answer» <P> Solution :From `v=v_(0)+gt`v=gt `therefore`Momentum ,p=`m_(p)v=m_(p)gt` `therefore lambda=(h)/(p)=(h)/(m_(p)"gt")=(6.625xx10^(-34))/(1.67xx10^(-27)xx10xx10)` `therefore lambda=3.96xx10^(-9)m` |
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