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A proton initially has vec v = 4.0 hati- 2.0 hatj + 3.0 hatk and then 4.0 slater has vec v = -2.0 hati - 2.0 hatj + 5.0hatk(in meter per second) for that 4.0s what are (a) the proton's average acceleration vec a_(avg)in unit vector notation (b) the magnitude of vec a_(avg) and (c ) the angle between veca_(avg) and the positive direction of the x axis ?

Answer»

Solution :We use EQ. with VEC v_1` designating the initial VELOCITY and `vec v_2` designating the later one.
(a) The AVERAGE acceleration during the `Delta t = 4s` interval is
`vec a_(avg) = ((-2.0 hati - 2.0 hatj + 5.0 hatk) m//s - (4.0hati - 22hatj + 3.0 hatk)m//s)/(4s)`
` = (-1.5 m//s^2) hati + (0.5 m//s^2) hatk`
(b) The magnitude of `vec a_(avg) ` is
` sqrt( (-1.5 m//s^2)^2 + (0.5m//s^2)^2) = 1.6 m//s^2`
( c) Its angle in the xz plane (measured from the +x axis is one of these POSSIBILITIES :
` tan^(-1) ( (0.5m//s^2)/(-1.5 m//s^2)) = - 18^@ or162^@`


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