A proton (mass m) accelerated by a potential difference V flies through a uniform transverse magnetic field B. The field occupies a region of space by width 'd'. If alpha ' be the angle of deviation of proton from initial direction of motion (see figure), the value of sin a will be:

A proton (mass m) accelerated by a potential difference V flies throug

1.	A proton (mass m) accelerated by a potential difference V flies through a uniform transverse magnetic field B. The field occupies a region of space by width 'd'. If alpha ' be the angle of deviation of proton from initial direction of motion (see figure), the value of sin a will be:
Answer» <html><body><p>`qVsqrt( (pd )/(2m))`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/bd-389836" style="font-weight:bold;" target="_blank" title="Click to know more about BD">BD</a> sqrt((q)/( <a href="https://interviewquestions.tuteehub.com/tag/2mvbrbr-1837807" style="font-weight:bold;" target="_blank" title="Click to know more about 2MV">2MV</a>))`<br/>`(B)/(d )sqrt((q)/(2mV))`<br/>`(B )/(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)sqrt((qd)/(<a href="https://interviewquestions.tuteehub.com/tag/mv-1082193" style="font-weight:bold;" target="_blank" title="Click to know more about MV">MV</a>))`</p>Answer :B</body></html>

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A proton (mass m) accelerated by a potential difference V flies through a uniform transverse magnetic field B. The field occupies a region of space by width 'd'. If alpha ' be the angle of deviation of proton from initial direction of motion (see figure), the value of sin a will be:

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