A proton of energy `8 eV` is moving in a circular path in a uniform magnetic field. The energy of an alpha particle moving in the same magnetic field and along the same path will beA. 4eVB. 2eVC. 8eVD. 6eV

A proton of energy `8 eV` is moving in a circular path in a uniform ma

1.	A proton of energy `8 eV` is moving in a circular path in a uniform magnetic field. The energy of an alpha particle moving in the same magnetic field and along the same path will beA. 4eVB. 2eVC. 8eVD. 6eV
Answer» Correct Answer - C `E=(q^2B^2r^2)/(2m)` `therefore (E_alpha)/(E_P)=((q_alpha)/(q_P))^2 (m_p)/(m_alpha)=(4)/(1)xx(1)/(4)` `therefore E_alpha=E_p=8eV`

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A proton of energy `8 eV` is moving in a circular path in a uniform magnetic field. The energy of an alpha particle moving in the same magnetic field and along the same path will beA. 4eVB. 2eVC. 8eVD. 6eV

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