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A proton of mass `m` moving with a speed `v_(0)` apporoches a stationary proton that is free to move. Assuming impact parameter to be zero., i.e., head-on collision. How close will be incident proton go to other proton ?A. `e^(2)/(4piepsilonmv_(0)^(2)`B. `e^(2)/(piepsilon_(0)mv_(0)^(2)`C. `e^(2)/(mv_(0)^(2)`D. zero

Answer» Correct Answer - B
use : LCLM and conservation of energy . `Ie:mv_(0)=2mu-(1)`
` (mv_(0)^(2))/2=2xx1/2m(u_(0)/2)=e^(2)/(4piepsilonr)`


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